Excel Companion Appendix B |
LINEAR
OPTIMIZATION PROBLEMS USING EXCEL SOLVER
Overview of Working with Microsoft Excel Solver (taken from MS Office documentation)
Microsoft Excel Solver is a powerful optimization and resource allocation tool. It can help you to uncover the best uses of scarce resources so that desired goals such as profit can be maximized, or undesired goals such as cost can be minimized. Microsoft Excel Solver answers questions such as:
Instead of guessing over and over,
you can use Microsoft Excel Solver to find the best answer. When
you solve a problem using Solver, you:
After solving the problem, you can
create three types of reports that summarize the results of a
successful solution process.
When you save a workbook, the last
selections made in the Solver Parameters dialog box are retained
for each worksheet on which you have defined a Solver problem.
However, you can define more than one problem for a worksheet by
saving them individually using the Save Model button in the
Solver Options dialog box.
You can then use the Load Model
button to open a saved problem model.
You can also save the Solver
settings for the problem as a scenario using the Scenario
Manager.
See Also
Help
Adding, changing, or deleting constraints in Solver
Adjusting the Solver settings
Creating a report using Solver
Defining a problem using Solver
Saving and loading a problem model using Solver
Scenarios Command (Tools Menu)
Solver Command (Tools Menu)
Solving a problem using Solver
The Difference Between Linear and Nonlinear Problems
User's Guide
Chapter 29, "Using Solver to Analyze Multiple-Variable
Problem
Frontline Systems Inc. is the spreadhseet solver company that created the Solver Add-in for Microsoft Excel. Their home page http://www.frontsys.com contains announcements of new products and can lead you to technical information and resources including help with Solver, a tutorial on optimization, and a private Web for Solver users.
In order to use Excel as an
electronic assistant for solving Linear Programming problems you
must become familiar with (1) the basic steps involved in
building a spreadsheet model and (2) the sequence
of commands for using the Solver Add-In tool. Solver
must be installed on the network or on your hard drive. Ask for
assistance if you discover that Solver is not available
from the main menu under Tools.
An efficient way to learn to use Solver is to work through examples. We start with a simple two-variable LP problem and illustrate:
SITUATION:
Ace Tire Company manufactures two types of tires: Model P (the premium) and Model R (the regular). Model P sells for $95 per tire and costs $85 per tire to make, whereas Model R sells for $50 per tire and costs $42 per tire to make. To make one Model P tire, it requires two hours on Machine A and four hours on Machine B. On the other hand, to make one Model R tire, it takes nine hours on Machine A and three hours on Machine B. Production scheduling indicates that during the coming week Machine A will be available for at most 36 hours and Machine B for at most 42 hours. How many of each tire should the company make in the coming week in order to maximize its profit? What is this maximum profit?
The two decision variables in this model are the number of premium tires, x, and the number of regular tires, y. The objective is to find an optimal weekly production plan. That is, to determine the number of each type of tire to produce each week in order to maximize the total weekly profit. The formulation for this LP problem is given below:
Maximize Profit = 10x + 8y subject to constraints (1) - (4)
| (1) | 2x + 9y < 36 | Machine A time constraint |
| (2) | 4x + 3y < 42 | Machine B time constraint |
| (3) | x > 0 | non-negativity |
| (4) | y > 0 | non-negativity |
To prepare an Excel model for Solver, start by entering the relevant labels as shown below:
Associate cells B2 and C2 (now empty) with the decision variables whose names are "Premium" and "Regular". In Figure B_1 these two cells have been given borders and a very light shaded background simply to remind you that they contain the values of the decision variables, x and y. Each of the formulas entered in column D contains a reference to B2 and to C2. Columns B and C also contain important coefficients related to the profit function (row 3) and to the utilization of each type of machine (rows 4 and 5). When Solver goes to work, the values in these "target cells", B2 and C2, are adjusted as the software tool searches for an optimal solution. In this example, an optimal solution means "the maximum possible profit". The cell that will contain the optimal value of the objective function is referred to as the "target cell". In Figure B_1 this target cell is shaded in gray for identification purposes only. When you build your spreadsheet models, no shading will be required.
| Location | Cell formulas | Explanation |
| In cell B3 type | 10 | Each premium tire contributes $10 of profit. |
| In cell C3 type | 8 | Each regular tire contributes $8 of profit. |
| In cell D3 type | =B3*B2+C3*C2 | Our objective is to maximize the value of this target cell. |
| In cell B4 type | 2 | Each premium tire requires 2 hours on machine A. |
| In cell C4 type | 9 | Each regular tire requires 9 hours on machine A. |
| In cell B5 type | 4 | Each premium tire requires 4 hours on machine B. |
| In cell C5 type | 3 | Each regular tire requires 3 hours on machine B. |
| In cell D4 type | =B4*B2+C4*C2 | This cell contains the left-hand side (LHS) of the constraint for machine A. |
| In cell D5 type | =B5*B2+C5*C2 | This cell contains the LHS of the constraint for machine B. |
| In cell E4 type | 36 | This cell contains the right-hand side (RHS) of the constraint for machine A. |
| In cell E5 type | 42 | This cell contains the RHS of the constraint for machine B. |
| A | B | C | D | E | |
| 1 | Premium | Regular | Totals | Bounds | |
| 2 | Decision Variables | ||||
| 3 | Profit Function | 10 | 8 | 0 | |
| 4 | Machine A | 2 | 9 | 0 | 36 |
| 5 | Machine B | 4 | 3 | 0 | 42 |
Figure B_1
Notice that the formula for the
objective function and for the LHS of the constraints for machine
A and machine B all contain references to the decision variables
B2 and C2. Since cells B2 and C2 are currently empty, the values
of cells D3, D4, and D5 will also be zero. Figure B_2 displays
the formulas in column D rather than the values of
these cells as shown in Figure B_1.
| A | B | C | D | E | |
| 1 | Premium | Regular | Totals | Bounds | |
| 2 | Decision Variables | ||||
| 3 | Profit Function | 10 | 8 | =B3*B2+C3*C2 | |
| 4 | Machine A | 2 | 9 | =B4*B2+C4*C2 | 36 |
| 5 | Machine B | 4 | 3 | =B5*B2+C5*C2 | 42 |
Figure B_2
Figure B_3, below, serves as a
check on our formulas. By placing a 1 in both cells B2 and
C2, we obtain the values 18, 11, and 7 in column D. We interpret
these numbers as the values of the profit function, the number of
machine A hours used, and the number of machine B hours used,
respectively. Making exactly one Premium tire and exactly one
Regular tire would generate a profit of 18 dollars, using 11
hours on machine A and 7 hours on machine B.
| A | B | C | D | E | |
| 1 | Premium | Regular | Totals | Bounds | |
| 2 | Decision Variables | 1 | 1 | ||
| 3 | Profit Function | 10 | 8 | 18 | |
| 4 | Machine A | 2 | 9 | 11 | 36 |
| 5 | Machine B | 4 | 3 | 7 | 42 |
Figure B_3
Prior to our explorations with Solver,
we will first use trial and error to test different values of the
decision variables. This approach involves manually entering
trial values for the decision variables, B2 and C2, and then
inspecting the worksheet to determine if these values satisfy the
boundary conditions associated with the constraints.
[Before you begin to experiment
it would be a good idea to save your work as the file ACETIRE.xls].
If we make 3 Premium tires and 2
Regular tires then we would enter a 3 in cell B2 and a 2
in cell C2. From Figure B_4 we see that the corresponding dollar
profit would be 30 + 16 = 46. We can also see that this
production plan uses exactly 24 hours on machine A and 18 hours
on machine B, neither of which exceeds the total available time
on the respective machines.
| A | B | C | D | E | |
| 1 | Premium | Regular | Totals | Bounds | |
| 2 | Decision Variables | 3 | 2 | ||
| 3 | Profit Function | 10 | 8 | 46 | |
| 4 | Machine A | 2 | 9 | 24 | 36 |
| 5 | Machine B | 4 | 3 | 18 | 42 |
Figure B_4
You should keep a record of all points that you enter along with the corresponding values of the profit function.
| B | C | D | B | C | D | |
| Premium | Regular | Premium | Regular | |||
| B | C | D | B | C | D | |
| Premium | Regular | Premium | Regular | |||
Is it feasible to make 5 Premium
and 4 Regular tires? Why or why not? When you are finished
experimenting, restore the worksheet to look like Figure B_1 with
zeros (or like Figure B_3 with ones). Keep in mind that cell B2
corresponds to the decision variable x, the number of
Premium tires, and cell C2 corresponds to the decision variable y,
the number of Regular tires. We have now prepared a spreadsheet
which is at least adequate for investigation by the Solver
Add-in tool. Later will consider some modifications which are
more efficient for preparing worksheets for Solver,
especially those that have more variables and constraints than
this small example.
When you load Solver from
the Tools menu, a dialog box entitled Solver Parameters
will appear. Your task at this stage is to fill in the blank
dialog box, Figure B_5, with the parameters as shown in Figure
B_6.
Figure B_5
Figure B_6
The first entry to be specified is
Set Target Cell. Solver may make a guess about the
location of the target cell. In this case the formula in column D
and row 3 is the correct target cell so click on cell D3. Next
move to the Equal to row and click on the Max
button. This will direct Solver to maximize the weekly
profit from the two types of tires. Buttons for Min
and Value will be blank since only one
of these buttons can be in effect at any one time. Next move to
the box By Changing Cells. The entry here should appear as
$B$2:$C$2, the absolute address of the range of cells which
contain the decision variables. Note: If Solver is
successful at finding an optimal solution then B2:C2 will be the
cells into which Solver will store these optimal values.
Next move to the Subject to the
Constraints box. A dotted rectangle will appear in this box.
Click on the Add button and a new dialog box entitled Add
Constraint will appear:
Figure B_7 |
Cells D4 and D5 of the spreadsheet contain the formula for the left hand sides (LHS) of the machine constraints, These values should be respectively less than or equal to (<=) the right hand sides (RHS) of the boundary values which are stored in cells E4 and E5. |
Click in the Cell Reference
box and highlight cells D4:D5 on the worksheet. You should
see the <= sign in the middle box. If not, click on the
black down arrow to the right and select the <= sign.
This sets the direction of the constraint. Click in the
Constraint box and then highlight cells E4:E5, the cells
containing the expressions for the RHS of the constraints.
Lastly press the OK button in the dialog box and you will
be returned to the Solver Parameters dialog box. This time
you will see the constraint highlighted in the Subject to
Constraints box. It should read: $D$4:$D$5 <= $E$4:$E$5.
If you make an error, move the cursor over to the Change key and the Change Constraint dialog box will appear. It should look similar to the Add Constraint dialog box and the same instructions apply as before. Move the cursor over to where the change has to be made, make the change, and press OK to return to the Solver Parameters dialog box. Now the non-negativity constraints must be made explicit. Click on the Add button. When the Add Constraint dialog box appears, include the non-negativity constraints as follows.
Click in the Cell Reference
box on the left and then highlight B2:C2 (the locations of the
decision variables). In the inequality box select the >=
direction and then enter 0 in the Constraint box on the
right. Both sets of constraints should be visible in the Subject
to Constraints box when you click on OK and return to
the Solver Parameters box. Before you go on, compare your
parameters with those in Figure B_6. Next click on the Options
button. A new dialog box appears entitled Solver Options.
Click on the check box Assume Linear Model. This instructs
Solver to check that the objective function and the
constraints are indeed linear and to use a special algorithm,
called the simplex method, to solve the problem. Turning on this
checkbox is likely to improve the time it takes for Excel to find
a solution (which is important for larger models). The setup of
the problem is now complete.
Figure B_8 |
For now , ignore the rest of the options. Most of these have to do with default settings and solving non-linear optimization problems. Click on the OK button and return to the Solver Parameters dialog box. Click on the Solve button and Solver will proceed to search for the optimum solution. |
Figure B_9 |
Information about the search for an optimal solution will appear in the status bar at the lower left part of your screen. |
When Solver has finished, another dialog box will appear indicating whether or not a solution was found. Since the search was successful a solution appears on the worksheet. For managers, no solution is complete without a report containing an interpretation and a conclusion. The dialog box in Figure B_9 contains references to the Excel Solver completion reports Answers, Sensitivity, and Limits. As you learn more about linear programming, you will want to generate and interpret Sensitivity and/or Limits reports. For now, we will generate just an Answer report. First highlight Answer in the Reports box and then click on the OK box.
The answer report for this two variable problem should look like Figure B_10 below
Figure B_10
Checking the button Keep Solver
Solution instructs Solver to display the
optimal values of each variable on the spreadsheet. If you
choose Restore Original Values, then Solver will
restore these variables to their original values. Saving the
spreadsheet as the file ACETIRE.XLS on your data diskette
will also save the Solver parameters in your model along
with the spreadsheet data and the Answer Report. Each Answer Report is
numbered and identified as a tabbed sheet.
New decision variables and/or
additional constraints can be introduced in the spreadsheet at
any point. For example, suppose Ace Tire decides to make a third
model which they refer to as the Discount tire. To make one Model
D will require four hours on machine A and four hours on machine
B. To improve the quality of their products, Ace Tire must also
bring in a new finishing machine, machine C, which can be
utilized for at most 30 hours per week. The machine C utilization
requirements are as follows: three hours per Premium tire,
one-half hour per Discount tire, and two hours per Regular tire.
The profit function also changes. The new profit function will be
defined by the formula Profit = 8*Premium + 9*Discount +
7*Regular.
To add a new decision variable
for Discount tires, we must first insert a new column
Highlight the column containing the data for Regular tires and then select Insert Columns
| Enter the label | Discount | in cell C1 | |
| Enter the value | 9 | in cell C3 | |
| Enter the value | 4 | in cell C4 | |
| Enter the value | 4 | in cell C5 |
To add a new constraint in row
6 for machine C
| Enter the label | Machine C | in cell A6 | |
| Enter the value | 3 | in cell B6 | |
| Enter the value | 0.5 | in cell C6 | |
| Enter the value | 2 | in cell D6 | |
| Enter the value | 30 | in cell F6 |
The formulas in cells E3:E6
should be modified as follows
| E3 should contain the formula | =B3*B2+C3*C2+D3*D2 | |
| E4 should contain the formula | =B4*B2+C4*C2+D4*D2 | |
| E5 should contain the formula | =B5*B2+C5*C2+D5*D2 | |
| E6 should contain the formula | =B6*B2+C6*C2+D6*D2 |
When the modified worksheet is
ready for Solver, the values and formulas should look like
Figure B_11.
| A | B | C | D | E | F | |
| 1 | Premium | Discount | Regular | Totals | Bounds | |
| 2 | Decision variables: | 0 | 0 | 0 | ||
| 3 | Profit | 8 | 9 | 7 | =B3*B2+C3*C2+D3*D2 | |
| 4 | Machine A | 2 | 4 | 9 | =B4*B2+C4*C2+D4*D2 | 36 |
| 5 | Machine B | 4 | 4 | 3 | =B5*B2+C5*C2+D5*D2 | 42 |
| 6 | Machine C | 3 | 0.5 | 2 | =B6*B2+C6*C2+D6*D2 | 30 |
Figure B_11
Figure B_12 shows the parameters of the completed Solver dialog box.
|
Figure B_12
Make sure that Linear
Model has been checked under Options before you run Solver. Once Solver
indicates
that a solution has been found, select the Answer Report
before you click the OK button.
Note that Answer
Report shown in Figure B_13 shows the original and final values
of the target cell and the changing cells. It also lists the
constraints and gives important information about each
constraint.
Figure B_13
INTEGER SOLUTIONS
If you are interested in looking for an optimal solution in which decision variables are all integers then you must invoke Solver again and add an int constraint to cells B2, C2, and D2. See Figure B_14 for the new Answer Report. With integer programming models you should not be surprised if Solver returns a message indicating that a solution could not be found under the given conditions.
Figure B_14
IMPROVING THE EFFICIENCY OF
BUILDING AND INTERPRETING LARGER MODELS
The AceTire worksheet in Figure
B_11 has only three decision variables, three <
constraints, and one > constraint (non-negativity). It
is not unusual for real - world linear optimization problems to
have hundreds (or even thousands) of variables and constraints.
Some examples of very large LP models occur in airline
reservation systems and the design of telephone switching
circuitry. The nutrition model below has nine variables and
thirteen constraints. Before we examine this model, we will first
learn how to prepare spreadsheets for Solver that uses a more
efficient method of entering data and formulas. These
modifications will also make it easier for us to read the reports
and interpret the results.
To understand this new approach we
will re-build the entire AceTire worksheet starting with a
new (blank) worksheet. As you will see, the major difference will
be in the way we build the formulas for the target cell, E3, and
for the cells immediately below the target cell.
The formula for the objective
function in cell E3 could be entered as
=B3*B2+C3*C2+D3*D2
Cells E4, E5, and
E6 must contain formulas for the LHS of each machine constraint.
Using the earlier method, these formulas were expressed as:
=B4*B2+C4*C2+D4*D2
=B5*B2+C5*C2+D5*D2
=B6*B2+C6*C2+D6*D2
In each of these
four formulas, notice that the values in columns B, C, and D of
each row (rows 3, 4, 5, and 6) are multiplied by the
corresponding values of the decision variables which are always
in cells B2, C2, and D2. These individual products are then added
together, as a "sum of products". Using Excel's
SUMPRODUCT function, the formula for cell E3 can be efficiently
implemented as
= SUMPRODUCT( B3: D3, $B$2:$D$2)
References to the range of cells B2, C2, and D2 with $ signs in front of the column and row position, are called "absolute references". This has the effect of insuring that a reference to such a cell will not change if the formula containing the absolute reference is copied to another location. The LHS (left-hand side) formulas for cells E4, E5, and E6 can be easily obtained by copying cell E3, which contains the formula = SUMPRODUCT( B3: D3, $B$2:$D$2), into the three rows directly below E3. One easy way to perform this action is to select cell E3, locate its fill handle in the lower right corner of the cell's border, and then click and drag the cursor (in the shape of a crossbar ) through the three rows while holding down the left mouse button. Once the range E4: E6 has been highlighted, let up on the left mouse button and the filling down will be accomplished. In Figure B_15, below, column E shows the formula for the objective function (shaded) and the LHS of the constraints for each machine.
| A | B | C | D | E | F | |
| 1 | Premium | Discount | Regular | Totals | Bounds | |
| 2 | Decision Variables: | 0 | 0 | 0 | ||
| 3 | Profit Function | 8 | 9 | 7 | =SUMPRODUCT(B3:D3,$B$2:$D$2) | |
| 4 | Machine A | 2 | 4 | 9 | =SUMPRODUCT(B4:D4,$B$2:$D$2) | 36 |
| 5 | Machine B | 4 | 4 | 3 | =SUMPRODUCT(B5:D5,$B$2:$D$2) | 42 |
| 6 | Machine C | 3 | 0.5 | 2 | =SUMPRODUCT(B6:D6,$B$2:$D$2) | 30 |
Figure B_15
At this point the
worksheet is ready for you to enter the parameters as shown in
Figure B_16.
|
Figure B_16
Make sure that Linear Model has been selected under Options. Click on Solve and convince yourself that this more efficient procedure for building the worksheet in Figure B_15 is equivalent to the original method.
A MINIMAL COST NUTRITION
PROBLEM
The efficiencies
of building a model in the new way will become more apparent as
you investigate the following nutrition/diet problem.
Ten male soccer players are all between 19 and 22 years old and weigh from 154 to 177 pounds. The recommended daily intake of calories, protein, fat, cholesterol, and sodium for each individual are the recommended limits found to the right side of the table Nutrition Information per Serving below. The team intends to eat together at a local McDonald's. They know that no one can order 1.7 hamburgers but they could order 17 and cut them up. Their coach has advised them to avoid carbonated beverages. Most of them will drink water and orange juice. From their previous trips to McDonald's they have sampled the food, checked the prices, and obtained nutrition information per serving. Their main concerns are (1) meeting the recommended daily requirements including 100 % of the RDA for Vitamins A and C, Thiamin, Riboflavin, Niacin, Calcium, and Iron (2) staying within the recommended limits for fat, cholesterol, and sodium (3) keeping their costs under $10.00 per person and (4) maintaining good relationships with the busy restaurant staff. From the 80 possible choices on the menu they have decided to limit their choices to the nine shown in Figure B_17.
The following
tables show 1994 unit prices at a local McDonald's and data taken
from a 1993 McDonald's publication entitled Nutrition
Information per Serving. This data has been stored in the
file MCDNLD9.xls.
| HB | MF | GS | SBE | W | BAP | MCOOKIE | OJ | HCLFYS |
| $0.59 | $1.05 | $1.89 | $1.49 | $0.99 | $0.85 | $0.65 | $0.89 | $0.95 |
| Hamburger | Medium Fries | Garden Salad | Sausage Biscuit/w Egg | Wheaties | Baked Apple Pie | McDonald's Cookies | Orange Juice | Hot Caramel Lowfat Frozen Yogurt Sundae |
Figure B_17
Recommended
limits: Based on Males between 19-22 years of age and
weighing 154 to 177 lbs.
| Calories | 255 | 320 | 50 | 505 | 90 | 290 | 290 | 80 | 270 | >= | 2900 |
| Protein (g) | 12 | 4 | 4 | 19 | 2 | 3 | 4 | 1 | 7 | >= | 56. |
| Vitamin A (%RDA) | 4 | * | 90 | 6 | 20 | * | * | 2 | 6 | >= | 100 |
| Vitamin C (%RDA) | 4 | 20 | 35 | * | 20 | * | * | 120 | * | >= | 100 |
| Thiamin (%RDA) | 20 | 15 | 6 | 30 | 20 | 10 | 15 | 10 | 6 | >= | 100 |
| Riboflavin (%RDA) | 10 | * | 6 | 20 | 20 | 4 | 10 | 2 | 20 | >= | 100 |
| Niacin (%RDA) | 20 | 15 | 2 | 20 | 20 | 10 | 10 | 2 | * | >= | 100 |
| Calcium (%RDA) | 10 | * | 4 | 10 | 2 | 2 | * | 2 | 20 | >= | 100 |
| Iron (%RDA) | 15 | 4 | 8 | 20 | 20 | 6 | 10 | 2 | * | >= | 100 |
| Fat (g) | 9 | 17 | 2 | 33 | 1 | 15 | 9 | 0 | 3 | <= | 96 |
| Cholesterol (mg) | 37 | 0 | 65 | 260 | 0 | 0 | 0 | 0 | 13 | <= | 300 |
| Sodium (mg) | 490 | 150 | 70 | 1210 | 220 | 90 | 300 | 20 | 180 | <= | 3000 |
Note: * signifies the amount is insignificantly small
Figure B-18
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Given the information in Figures 17 and Figure 18, your task is to build the worksheet and then use Solver. Note that there will be ten > constraints (counting non-negativity) and three < constraints. Load Solver and enter the appropriate parameters as shown in Figure B_19. Be sure to check Linear Model in Options and then Solve. |
|
In Figure B_20 the optimal
solutions have been saved with the worksheet.
| A | B | C | D | E | F | G | H | I | J | K | L |
| Menu Item | HB | MF | GS | SBE | W | BAP | MCOOKIE | OJ | HCLFYS | Totals | Bounds |
| Decision Variables | 3.68 | 0.00 | 0.63 | 0.00 | 0.60 | 3.00 | 0.90 | 0.43 | 2.63 | ||
| Cost Function | $0.59 | $1.05 | $1.89 | $1.49 | $0.99 | $0.85 | $0.65 | $0.89 | $0.95 | $9.97 | |
| Calories | 255 | 320 | 50 | 505 | 90 | 290 | 290 | 80 | 270 | 2900.00 | 2900 |
| Protein (g) | 12 | 4 | 4 | 19 | 2 | 3 | 4 | 1 | 7 | 79.31 | 56 |
| Vitamin A (%RDA) | 4 | 90 | 6 | 20 | 2 | 6 | 100.00 | 100 | |||
| Vitamin C (%RDA) | 4 | 20 | 35 | 20 | 120 | 100.00 | 100 | ||||
| Thiamin (%RDA) | 20 | 15 | 6 | 30 | 20 | 10 | 15 | 10 | 6 | 152.86 | 100 |
| Riboflavin (%RDA) | 10 | 6 | 20 | 20 | 4 | 10 | 2 | 20 | 127.01 | 100 | |
| Niacin (%RDA) | 20 | 15 | 2 | 20 | 20 | 10 | 10 | 2 | 126.61 | 100 | |
| Calcium (%RDA) | 10 | 4 | 10 | 2 | 2 | 2 | 20 | 100.00 | 100 | ||
| Iron (%RDA) | 15 | 4 | 8 | 20 | 20 | 6 | 10 | 2 | 100.00 | 100 | |
| Fat (g) | 9 | 17 | 2 | 33 | 1 | 15 | 9 | 0 | 3 | 96.00 | 96 |
| Cholesterol (mg) | 37 | 0 | 65 | 260 | 0 | 0 | 0 | 0 | 13 | 211.24 | 300 |
| Sodium (mg) | 490 | 150 | 70 | 1210 | 220 | 90 | 300 | 20 | 180 | 3000.00 | 3000 |
Figure B_20
The target cell and the cells containing the decision variables are shaded as before for ease of identification. As you might expect, the optimal solution which corresponds to a minimum cost does not have integer values.
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Copyright © Joseph F. Aieta, Babson
College 1997